A satellite orbits just above Earth’s surface with period T. If Earth density is d and gravitational constant is G, the quantity 3π/(Gd) equals:
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A satellite orbits just above Earth’s surface with period T. If Earth density is d and gravitational constant is G, the quantity 3π/(Gd) equals:

G1 Physics · Accepted Answer

Step 1: The near-surface period satisfies T=2π√[R³/(GM)]. Since M=(4π/3)dR³, substitute into T²=4π²R³/(GM). Step 2: This yields T²=4π²/[G(4π/3)d]=3π/(Gd). Final answer: D — T².