A series LCR circuit has R = 100 Ω and is connected to 200 V AC at angular frequency 300 rad s⁻¹. With C removed, current lags by 60°. With L removed, current leads by 60°. Find the current (A) in complete series LCR circuit.
Physics · Mixed Chapter
JEE Main Practice

Question

A series LCR circuit has R = 100 Ω and is connected to 200 V AC at angular frequency 300 rad s⁻¹. With C removed, current lags by 60°. With L removed, current leads by 60°. Find the current (A) in complete series LCR circuit.

Physics · Mixed Chapter

G1 Physics · Accepted Answer

Step 1 — Without C, tan60° = Xₗ/R, so Xₗ = √3 R. Step 2 — Without L, tan60° = X꜀/R, so X꜀ = √3 R. Step 3 — In full circuit X = Xₗ − X꜀ = 0, so impedance Z = √(R² + X²) = R = 100 Ω. Step 4 — I₍rms₎ = 200/100 = 2 A.