A 0.8 kg collar slides on smooth fixed circular path radius 0.4 m; string over small fixed pulleys applies constant 40 N pulling force. It moves from A (rest) to B at speed v₀. Find v₀/√2 (g = 10 m s⁻²). [See Image.]
Physics · Mixed Chapter
JEE Main Practice

Question

A 0.8 kg collar slides on smooth fixed circular path radius 0.4 m; string over small fixed pulleys applies constant 40 N pulling force. It moves from A (rest) to B at speed v₀. Find v₀/√2 (g = 10 m s⁻²). [See Image.]

Physics · Mixed Chapter

G1 Physics · Accepted Answer

Step 1 — The string is pulled with constant tension T = 40 N, causing the collar to move around the circular groove. Step 2 — Work done by tension equals tension times reduction of total string length on the side of force application. Step 3 — Gravitational work is Wg = mg(yₐ−yᵦ), with y coordinates read from diagram. Step 4 — Work-energy theorem: (1/2)mv²₍B₎ = TΔℓ + mg(yₐ−yᵦ). The source prints requested parameter 4. QUALITY FLAG — Length changes and actual question expression require original…