The relation g = 4π²L/T² is used to find g. If percentage errors in L and T are 2% and 3%, respectively, find the maximum percentage error x in g.
Physics · Mixed Chapter
JEE Main Practice

Question

The relation g = 4π²L/T² is used to find g. If percentage errors in L and T are 2% and 3%, respectively, find the maximum percentage error x in g.

G1 Physics · Accepted Answer

Step 1: Treat 4π² as exact. The measured relation is g ∝ LT⁻². Step 2: Maximum fractional error is Δg/g = ΔL/L + 2ΔT/T. Step 3: Percentage error = 2 + 2×3 = 8%. Thus x = 8.