Two temperatures are recorded as (40.6 ± 0.4) °C and (78.4 ± 0.2) °C. Rise in temperature is written (37.8 ± 0.k) °C. Find k.
Physics · Mixed Chapter
JEE Main Practice

Question

Two temperatures are recorded as (40.6 ± 0.4) °C and (78.4 ± 0.2) °C. Rise in temperature is written (37.8 ± 0.k) °C. Find k.

G1 Physics · Accepted Answer

Step 1: Temperature rise = 78.4 − 40.6 = 37.8 °C. Step 2: For the maximum absolute error of a difference, add the errors: 0.2 + 0.4 = 0.6 °C. Step 3: The reading is (37.8 ± 0.6) °C. Thus k = 6.