Successive balls are thrown vertically upward, one when the preceding ball reaches its maximum height. Maximum height is 5 m. If g = 10 m/s², find the number thrown per second.
Physics · Mixed Chapter
JEE Main Practice

Question

Successive balls are thrown vertically upward, one when the preceding ball reaches its maximum height. Maximum height is 5 m. If g = 10 m/s², find the number thrown per second.

G1 Physics · Accepted Answer

Step 1: At maximum height, u² = 2gH ⇒ u = √(2×10×5) = 10 m/s. Step 2: Time to reach maximum height is t_up = u/g = 10/10 = 1 s. Step 3: One ball is launched after every 1 s, so the launch rate is 1 s⁻¹.