Heat dissipated in a circuit is H=I²Rt. Percentage errors in R, I and t are 1%, 2%, and 1%, respectively. Find maximum percentage error x in H.
Physics · Mixed Chapter
JEE Main Practice

Question

Heat dissipated in a circuit is H=I²Rt. Percentage errors in R, I and t are 1%, 2%, and 1%, respectively. Find maximum percentage error x in H.

G1 Physics · Accepted Answer

Step 1: Joule heating relation H=I²Rt. Step 2: Maximum percentage error is ΔH/H = 2ΔI/I + ΔR/R + Δt/t. Step 3: Substitute 2×2%+1%+1%=6%. Therefore x=6.