An ideal gas has internal energy U=2PV. It expands from V₀ to 3V₀ at constant external pressure P₀. Heat absorbed is N P₀V₀. Find N.
Physics · Mixed Chapter
JEE Main Practice

Question

An ideal gas has internal energy U=2PV. It expands from V₀ to 3V₀ at constant external pressure P₀. Heat absorbed is N P₀V₀. Find N.

G1 Physics · Accepted Answer

Step 1: Assuming quasi-static isobaric expansion at P₀, ΔU=2P₀(3V₀−V₀)=4P₀V₀. Step 2: Work done by gas W=P₀(3V₀−V₀)=2P₀V₀. Step 3: First law Q=ΔU+W=6P₀V₀. Thus N=6.