A body revolves in a circle of radius 30 m under a centripetal force of 400 N. Find its kinetic energy (kJ).
Physics · Mixed Chapter
JEE Main Practice

Question

A body revolves in a circle of radius 30 m under a centripetal force of 400 N. Find its kinetic energy (kJ).

G1 Physics · Accepted Answer

Step 1: Centripetal force F = mv²/r. Step 2: Kinetic energy K = ½mv² = ½Fr. Step 3: K = ½ × 400 × 30 = 6000 J = 6 kJ.