6 g of steam at 100°C mixes with 6 g of ice at 0°C. Find the mass of steam remaining uncondensed (g). Use Lᵥ = 540 cal/g, L𝒇 = 80 cal/g.
Physics · Mixed Chapter
JEE Main Practice

Question

6 g of steam at 100°C mixes with 6 g of ice at 0°C. Find the mass of steam remaining uncondensed (g). Use Lᵥ = 540 cal/g, L𝒇 = 80 cal/g.

G1 Physics · Accepted Answer

Step 1: To melt 6 g ice, heat required = 6×80 = 480 cal. Step 2: To warm the resulting 6 g water from 0°C to 100°C requires 6×1×100 = 600 cal. Step 3: Total = 1080 cal, which condensing steam supplies. Thus condensed steam = 1080/540 = 2 g. Step 4: Steam remaining = 6 − 2 = 4 g.