A particle starts from rest. In the given acceleration–time graph a falls uniformly from 10 m/s² at t=0 to 0 at t=11 s. Find average acceleration over 0≤t≤11 s (m/s²).
Physics · Mixed Chapter
JEE Main Practice

Question

A particle starts from rest. In the given acceleration–time graph a falls uniformly from 10 m/s² at t=0 to 0 at t=11 s. Find average acceleration over 0≤t≤11 s (m/s²).

G1 Physics · Accepted Answer

Step 1: Average acceleration over interval is Δv/Δt = (1/11)∫₀¹¹a(t)dt. Step 2: Area below graph is triangle with base 11 s and height 10 m/s²: Δv=½×11×10=55 m/s. Step 3: aavg=55/11=5 m/s².