A rod of length 1 m, area 0.75 m² and conductivity K=200 W m⁻¹ K⁻¹ carries steady heat 6000 J/s. Temperature difference is 10p K. Find p.
Physics · Mixed Chapter
JEE Main Practice

Question

A rod of length 1 m, area 0.75 m² and conductivity K=200 W m⁻¹ K⁻¹ carries steady heat 6000 J/s. Temperature difference is 10p K. Find p.

G1 Physics · Accepted Answer

Step 1: Fourier law for steady 1D conduction: Q̇=KAΔT/L. Step 2: ΔT=Q̇L/(KA)=(6000×1)/(200×0.75)=40 K. Step 3: 10p=40 ⇒p=4.