110 J of heat is added to a gaseous system whose internal energy is 40 J. The amount of external work done is:
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Question

110 J of heat is added to a gaseous system whose internal energy is 40 J. The amount of external work done is:

G1 Physics · Accepted Answer

Step 1: Interpret 40 J as the increase in internal energy during the heating process, as intended by the question. Step 2: First law: Q = ΔU + W. Step 3: Substitute Q = 110 J and ΔU = 40 J. Step 4: W = 110 − 40 = 70 J. Final answer: (B) 70 J.