At 10°C, the value of density of a fixed mass of an ideal gas divided by its pressure is x. At 110°C this ratio is:
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At 10°C, the value of density of a fixed mass of an ideal gas divided by its pressure is x. At 110°C this ratio is:

G1 Physics · Accepted Answer

Step 1: From PV = nRT and ρ = m/V, we obtain ρ/P = M/(RT) for a gas of molar mass M. Step 2: For fixed gas composition, ρ/P ∝ 1/T, where T is in kelvin. Step 3: T₁ = 10 + 273 = 283 K and T₂ = 110 + 273 = 383 K. Step 4: (ρ/P)₂/(ρ/P)₁ = T₁/T₂ = 283/383. Final answer: (D) (283/383)x.