A diatomic gas initially at 18°C is compressed adiabatically to one-sixth of its original volume. The temperature after compression will be:
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Question

A diatomic gas initially at 18°C is compressed adiabatically to one-sixth of its original volume. The temperature after compression will be:

G1 Physics · Accepted Answer

Step 1: For adiabatic ideal-gas compression, TVᵞ⁻¹ = constant; for a diatomic gas without vibration, γ = 7/5. Step 2: T₁ = 18 + 273 = 291 K. The question text says V₂ = V₁/6. Step 3: Then T₂ = 291 × (V₁/V₂)²ᐟ⁵ = 291 × 6²ᐟ⁵ ≈ 596 K (≈ 323°C). Step 4: This answer is not in the supplied options. The printed solution instead substitutes V₂ = V₁/8 and obtains T₂ = 291 × 8²ᐟ⁵ ≈ 668.4 K. Final printed answer: (B) 668.4 K, but the source stem (one-sixth) and source worked solution (one-eighth) contradi…