Two point charges A and B having charges +Q and -Q, respectively, are placed at a certain distance apart and the force acting between them is F. If 25% charge of A is transferred to B, then the force between the charges becomes:
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Question

Two point charges A and B having charges +Q and -Q, respectively, are placed at a certain distance apart and the force acting between them is F. If 25% charge of A is transferred to B, then the force between the charges becomes:

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G1 Physics · Accepted Answer

Step 1: Initially F = kQ²/r². Step 2: Transferred positive charge is Q/4; new charges are qₐ = 3Q/4 and qᵦ = −3Q/4. Step 3: F′ = k|qₐqᵦ|/r² = (9/16)kQ²/r² = 9F/16.

Two point charges A and B having charges +Q and −Q, respectively, are placed at a certain distance apart and the force acting between them is F. If 25% charge of A is transferred to B, then the force between the charges becomes: