The value of electric potential at a distance of 9 cm from the point charge 4 × 10⁻⁷ C is (1/(4πε₀) = 9 × 10⁹ N m² C⁻²):
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The value of electric potential at a distance of 9 cm from the point charge 4 × 10⁻⁷ C is (1/(4πε₀) = 9 × 10⁹ N m² C⁻²):

G1 Physics · Accepted Answer

Step 1: For a point charge, V = kQ/r. Step 2: Substitute k = 9 × 10⁹, Q = 4 × 10⁻⁷ C and r = 0.09 m. Step 3: V = 9 × 10⁹ × 4 × 10⁻⁷/0.09 = 4 × 10⁴ V.