The electric potential at a point in free space due to charge Q coulomb is Q × 10¹¹ V. The electric field at that point is:
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The electric potential at a point in free space due to charge Q coulomb is Q × 10¹¹ V. The electric field at that point is:

G1 Physics · Accepted Answer

Step 1: Potential due to a point charge is V = Q/(4πε₀r) = Q × 10¹¹. Step 2: Therefore 1/r = 4πε₀ × 10¹¹. Step 3: Electric field E = Q/(4πε₀r²). Step 4: Insert 1/r: E = [Q/(4πε₀)](4πε₀ × 10¹¹)² = 4πε₀Q × 10²² V/m.