Two dielectric slabs of dielectric constants K₁ and K₂ (K₁ > K₂) are inserted between plates of parallel plate capacitors. For variation of electric field E between plates with distance d at constant potential, which graph is correct? [Diagram: Image]
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Question

Two dielectric slabs of dielectric constants K₁ and K₂ (K₁ > K₂) are inserted between plates of parallel plate capacitors. For variation of electric field E between plates with distance d at constant potential, which graph is correct? [Diagram: Image]

Options

G1 Physics · Accepted Answer

Step 1: For dielectric slab under a fixed free charge distribution, electric field E = σ𝒻/(Kε₀). Step 2: Thus larger K produces smaller field. Step 3: Compare successive region values in original graph and select step profile (C).