A 12 pF capacitor is connected to a 50 V battery. The electrostatic energy stored in the capacitor in nJ is:
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A 12 pF capacitor is connected to a 50 V battery. The electrostatic energy stored in the capacitor in nJ is:

G1 Physics · Accepted Answer

Step 1: U = ½CV². Step 2: C = 12 × 10⁻¹² F and V = 50 V. Step 3: U = ½×12×10⁻¹²×50² = 15×10⁻⁹ J = 15 nJ.