The energy required to charge a parallel-plate condenser of plate separation d and plate area A, such that the uniform electric field between the plates is E, is:
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The energy required to charge a parallel-plate condenser of plate separation d and plate area A, such that the uniform electric field between the plates is E, is:

G1 Physics · Accepted Answer

Step 1: Energy density of electrostatic field is u = ½ε₀E². Step 2: Field occupies volume A×d. Step 3: U = (½ε₀E²)Ad.