If the potential of a capacitor having capacity 6 μF is increased from 10 V to 20 V, then increase in its energy is:
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If the potential of a capacitor having capacity 6 μF is increased from 10 V to 20 V, then increase in its energy is:

G1 Physics · Accepted Answer

Step 1: U = ½CV². Step 2: Increase ΔU = ½C(V₂² − V₁²). Step 3: ΔU = ½ × 6×10⁻⁶ × (20² − 10²) = 3×10⁻⁶×300 = 9 × 10⁻⁴ J.