If a negligibly small current is passed through a wire 15 m long and resistance 5 Ω with uniform cross section 6 × 10⁻⁷ m², the coefficient of resistivity of its material is approximately:
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If a negligibly small current is passed through a wire 15 m long and resistance 5 Ω with uniform cross section 6 × 10⁻⁷ m², the coefficient of resistivity of its material is approximately:

G1 Physics · Accepted Answer

Step 1: Resistivity ρ = RA/L. Step 2: ρ = 5 × 6 × 10⁻⁷/15 = 2 × 10⁻⁷ Ω·m.