If the power dissipated in the 9 Ω resistor in the circuit shown is 36 W, the potential difference across the 2 Ω resistor is: [Diagram: Image]
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If the power dissipated in the 9 Ω resistor in the circuit shown is 36 W, the potential difference across the 2 Ω resistor is: [Diagram: Image]

G1 Physics · Accepted Answer

Step 1: Use P₉ = I₉² × 9 = 36 to obtain current through 9 Ω: I₉ = 2 A. Step 2: The 9 Ω and 4 Ω resistance branches are parallel; V = 9×2 = 18 V. Step 3: Current through 4 Ω is 18/4 = 4.5 A. Step 4: Source circuit values or topology must be checked for 2 Ω voltage.