The magnitude and direction of the current in the circuit shown with resistances 2 Ω and 1 Ω and 7 Ω and two cells 10 V and 5 V respectively is: [Diagram: Image]
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The magnitude and direction of the current in the circuit shown with resistances 2 Ω and 1 Ω and 7 Ω and two cells 10 V and 5 V respectively is: [Diagram: Image]

G1 Physics · Accepted Answer

Step 1: The batteries oppose: resultant emf Eₙ = 10−5 = 5 V. Step 2: All resistors in series, total Rₙ = 2+1+7 = 10 Ω. Step 3: I = Eₙ/Rₙ = 5/10 = 0.5 A. Step 4: Polarity of stronger 10 V cell determines current from A to B through E.