For the circuit shown with 2 V and 1 V cells and resistances of 1 Ω, 1 Ω and 4 Ω, the current I is: [Diagram: Image]
Options

Question

For the circuit shown with 2 V and 1 V cells and resistances of 1 Ω, 1 Ω and 4 Ω, the current I is: [Diagram: Image]

G1 Physics · Accepted Answer

Step 1: Cell emfs oppose; net emf E = 2−1 = 1 V (if polarities oppose). Step 2: All resistors in loop add to R = 1+1+4 = 6 Ω. Step 3: Calculated I = 1/6 A, which does not match printed key; recheck polarity and source circuit. If emfs aid, I = 3/6 = 0.5 A.