The potential difference (Vₐ − Vᵦ) between points A and B in the circuit where 2 A passes through 2 Ω and 1 Ω resistors and a 3 V cell is: [Diagram: Image]

Question

G1 Physics · Accepted Answer

Step 1: Going A→B along current, drop across 2 Ω is 2×2 = 4 V. Step 2: The cell (+ to −) gives a further drop of 3 V. Step 3: Drop across 1 Ω is 2×1 = 2 V. Step 4: Vₐ−Vᵦ = 4+3+2 = 9 V.