An electron moves in a circular path under a transverse magnetic field of 3.57 × 10⁻² T. If e/m = 1.76 × 10¹¹ C kg⁻¹, find its frequency of revolution.
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Question

An electron moves in a circular path under a transverse magnetic field of 3.57 × 10⁻² T. If e/m = 1.76 × 10¹¹ C kg⁻¹, find its frequency of revolution.

G1 Physics · Accepted Answer

Step 1: Cyclotron angular frequency of an electron in a uniform magnetic field is ω=|q|B/m. Step 2: Rotational frequency is f=ω/(2π)=(e/m)B/(2π). Step 3: Use e/m=1.76×10¹¹C/kg and B=3.57×10⁻²T: f≈(1.76×10¹¹×3.57×10⁻²)/(2π)≈1.0×10⁹Hz=1GHz. Answer A. Final answer: (A) 1 GHz.