A particle of charge q moves uniformly in a circular path of radius R with speed v. Find the magnitude of its equivalent magnetic dipole moment.
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A particle of charge q moves uniformly in a circular path of radius R with speed v. Find the magnitude of its equivalent magnetic dipole moment.

G1 Physics · Accepted Answer

Step 1: Equivalent current generated by charge q moving with speed v in circular path radius R is I = q/T. Step 2: Orbit period T = 2πR/v, so I = qv/(2πR). Step 3: Magnetic dipole moment magnitude μ = I × area = [qv/(2πR)]·πR² = qvR/2. Final answer: (D) qvR/2.