An iron rod of magnetic susceptibility 599 is placed in a magnetising field H = 1200 A m⁻¹. Given μ₀ = 4π × 10⁻⁷ T m A⁻¹, find the magnetic permeability μ of the material.
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An iron rod of magnetic susceptibility 599 is placed in a magnetising field H = 1200 A m⁻¹. Given μ₀ = 4π × 10⁻⁷ T m A⁻¹, find the magnetic permeability μ of the material.

G1 Physics · Accepted Answer

Step 1: Relative magnetic permeability is μᵣ = 1 + χₘ. Step 2: χₘ = 599 gives μᵣ = 600. Step 3: μ = μ₀μᵣ = (4π × 10⁻⁷) × 600 T m A⁻¹. Step 4: μ = 2.4π × 10⁻⁴ T m A⁻¹. Final answer: (D) 2.4π × 10⁻⁴ T m A⁻¹.