A coil of resistance 400 Ω is placed in a magnetic field. The magnetic flux linked with the coil varies as Φ = 50t² + 4 (Wb). Current through the coil at t = 2 s is:
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A coil of resistance 400 Ω is placed in a magnetic field. The magnetic flux linked with the coil varies as Φ = 50t² + 4 (Wb). Current through the coil at t = 2 s is:

G1 Physics · Accepted Answer

Step 1: |ε| = |dΦ/dt| = 100t V. Step 2: At t = 2 s, emf magnitude is 200 V. Step 3: Current I = |ε|/R = 200/400 = 0.5 A. Correct A. Final answer: (A) 0.5 A.