Find the energy stored in a 4 μH inductor carrying current 2 A.

Question

G1 Physics · Accepted Answer

Step 1: The magnetic energy stored in an inductor is U = (1/2)LI². Step 2: Convert L = 4 μH = 4 × 10⁻⁶ H and use I = 2 A. Step 3: U = (1/2)(4 × 10⁻⁶)(2)² = 8 × 10⁻⁶ J. Step 4: 8 × 10⁻⁶ J = 8 μJ. Final answer: (B) 8 μJ.