A long solenoid of 1000 turns carries current 4 A. Magnetic flux linked with each turn is 4 × 10⁻³ Wb. Calculate the self-inductance.
Options

Question

A long solenoid of 1000 turns carries current 4 A. Magnetic flux linked with each turn is 4 × 10⁻³ Wb. Calculate the self-inductance.

G1 Physics · Accepted Answer

Step 1: Self-inductance is defined through total flux linkage: NΦ = LI. Step 2: Given N = 1000, flux per turn Φ = 4 × 10⁻³ Wb, current I = 4 A. Step 3: L = NΦ/I = (1000 × 4 × 10⁻³)/4 = 1 H. Final answer: (C) 1 H.