Current in a coil changes from 10 A to zero in 0.5 s. If the average induced emf is 220 V, find its self-inductance.
Options

Question

Current in a coil changes from 10 A to zero in 0.5 s. If the average induced emf is 220 V, find its self-inductance.

G1 Physics · Accepted Answer

Step 1: Average induced emf magnitude in a coil is |ε| = L|ΔI|/Δt. Step 2: The current falls from 10 A to 0 A, so |ΔI| = 10 A and Δt = 0.5 s. Step 3: L = |ε|Δt/|ΔI| = (220 × 0.5)/10 = 11 H. Final answer: (C) 11 H.