A series LCR circuit has L = 10 mH, C = 1 μF and R = 100 Ω. Find the resonance frequency.
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A series LCR circuit has L = 10 mH, C = 1 μF and R = 100 Ω. Find the resonance frequency.

G1 Physics · Accepted Answer

Step 1: Resonance in a series LCR circuit occurs at ω₀ = 1/√(LC). Step 2: Here L = 10 mH = 10⁻² H and C = 1 μF = 10⁻⁶ F. Step 3: LC = 10⁻⁸ s²; ω₀ = 10⁴ rad/s. Step 4: f₀ = ω₀/(2π) ≈ 10000/(6.283) ≈ 1592 Hz = 1.59 kHz. Final answer: (B) 1.59 kHz.