In a series LCR circuit operating at resonance, what is the phase difference between applied AC voltage and current?
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In a series LCR circuit operating at resonance, what is the phase difference between applied AC voltage and current?

G1 Physics · Accepted Answer

Step 1: At LCR series resonance inductive and capacitive reactances cancel: ω₀L=1/(ω₀C). Step 2: Impedance becomes purely resistive Z=R and phase angle φ satisfies tanφ=(X(L)−X(C))/R=0. Step 3: Voltage and current are in phase (φ=0). Answer B. Final answer: (B) 0.