For a series LCR circuit at resonance, what is the power dissipated?

Question

G1 Physics · Accepted Answer

Step 1: At resonance ωL=1/(ωC), so net reactance is zero. Step 2: Total series impedance becomes purely resistive: Z=R. Step 3: Real power dissipated is P=I_rms² R = V_rms²/R. Final answer: (C) I²R.