Two slits in Young’s double-slit experiment are 1.5 mm apart and the screen is placed at a distance of 1 m from the slits. If the wavelength of light used is 600 × 10⁻⁹ m, the fringe separation is:
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Question

Two slits in Young’s double-slit experiment are 1.5 mm apart and the screen is placed at a distance of 1 m from the slits. If the wavelength of light used is 600 × 10⁻⁹ m, the fringe separation is:

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G1 Physics · Accepted Answer

Step 1: Fringe width β = λD/d. Step 2: Convert d = 1.5 × 10⁻³ m, λ = 600 × 10⁻⁹ m, D = 1 m. Step 3: β = (600 × 10⁻⁹ × 1)/(1.5 × 10⁻³) = 400 × 10⁻⁶ m = 4 × 10⁻⁴ m. Final answer: (D) 4 × 10⁻⁴ m.