Two slits in Young’s double-slit experiment have widths in the ratio 1:25. The ratio of the intensity at maxima and minima in the interference pattern, Iₘₐₓ/Iₘᵢₙ, is:
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Two slits in Young’s double-slit experiment have widths in the ratio 1:25. The ratio of the intensity at maxima and minima in the interference pattern, Iₘₐₓ/Iₘᵢₙ, is:

G1 Physics · Accepted Answer

Step 1: For similarly illuminated slits, individual intensities are proportional to slit widths; I₁/I₂ = 1/25. Step 2: Amplitude ratio √I₁:√I₂ = 1:5. Step 3: Iₘₐₓ/Iₘᵢₙ = (a₁+a₂)²/(a₂−a₁)² = (1+5)²/(5−1)² = 36/16 = 9/4. Final answer: (A) 9/4.