The energy of a hydrogen atom in the ground state is -13.6 eV. The energy of a He⁺ ion in its first excited state will be:
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Question

The energy of a hydrogen atom in the ground state is −13.6 eV. The energy of a He⁺ ion in its first excited state will be:

G1 Physics · Accepted Answer

The hydrogen-like energy formula is Eₙ = −13.6Z²/n² eV. For He⁺, Z = 2 and the first excited state is n = 2: E₂ = −13.6 × 4/4 = −13.6 eV. Answer: A.