The ground-state energy of hydrogen is −13.6 eV. When the electron is in the first excited state, its excitation energy is:

Question

G1 Physics · Accepted Answer

First excited state n = 2 has E₂ = −13.6/4 = −3.4 eV. Excitation energy E₂ − E₁ = −3.4 − (−13.6) = 10.2 eV. Answer: C.