Momentum of a photon of energy 1 MeV in kg·m/s is:

Question

G1 Physics · Accepted Answer

p = E/c. Convert 1 MeV = 10⁶ × 1.602 × 10⁻¹⁹ = 1.602 × 10⁻¹³ J. Thus p = 1.602 × 10⁻¹³/(3 × 10⁸) = 5.34 × 10⁻²² kg·m/s ≈ 5 × 10⁻²². Answer: A.