In the circuit, P and Q first pass through inverting gates and then into a NAND gate. What is the Boolean output Y?
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Question

In the circuit, P and Q first pass through inverting gates and then into a NAND gate. What is the Boolean output Y?

G1 Physics · Accepted Answer

First two inverting stages give P̅ and Q̅. Final NAND produces Y = NOT(P̅·Q̅). By De Morgan’s theorem NOT(P̅·Q̅) = P + Q. Final answer: Option C (OR).