In a vernier calliper, 20 vernier scale divisions (VSD) coincide with 16 main scale divisions (MSD). If 1 MSD = 1 mm, find the least count.
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Question

In a vernier calliper, 20 vernier scale divisions (VSD) coincide with 16 main scale divisions (MSD). If 1 MSD = 1 mm, find the least count.

G1 Physics · Accepted Answer

Step 1: 20 VSD = 16 MSD, so 1 VSD = (16/20) MSD = 0.8 MSD. Step 2: Since 1 MSD = 1 mm, 1 VSD = 0.8 mm. Step 3: Least count LC = 1 MSD − 1 VSD = 1.0 − 0.8 = 0.2 mm. Step 4: Convert to centimetres: 0.2 mm = 0.02 cm. Final answer: 0.02 cm (Option C).