An electrical section AB consists of a 1 H inductor, a 5 V cell and a 2 Ω resistor in series, in the polarities shown in the figure. At an instant the current is 2 A and is increasing at 1 A·s⁻¹. Find V(A) - V(B). Image
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Question

An electrical section AB consists of a 1 H inductor, a 5 V cell and a 2 Ω resistor in series, in the polarities shown in the figure. At an instant the current is 2 A and is increasing at 1 A·s⁻¹. Find V(A) - V(B). Image

Options

G1 Physics · Accepted Answer

Step 1: Moving from A to B in the direction of current, the inductor causes a potential drop L(di/dt) = 1 × 1 = 1 V. Step 2: The cell is crossed from positive to negative in the source figure, giving a 5 V drop. Step 3: Resistor drop is IR = 2 × 2 = 4 V. Step 4: Total drop V(A) − V(B) = 1 + 5 + 4 = 10 V. Final answer: V(A) − V(B) = 10 V (Option D).

An electrical section AB consists of a 1 H inductor, a 5 V cell and a 2 Ω resistor in series, in the polarities shown in the figure. At an instant the current is 2 A and is increasing at 1 A·s⁻¹. Find V(A) − V(B). Image