One mole of an ideal monatomic gas undergoes the clockwise rectangular cyclic process a → b → c → d → a on a P–V diagram: $P_high$ = 300 Pa, $P_low$ = 100 Pa, $V_left$ = 2 m³, $V_right$ = 5 m³. Find the NET heat supplied over one cycle. Image
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Question

One mole of an ideal monatomic gas undergoes the clockwise rectangular cyclic process a → b → c → d → a on a P–V diagram: $P_high$ = 300 Pa, $P_low$ = 100 Pa, $V_left$ = 2 m³, $V_right$ = 5 m³. Find the NET heat supplied over one cycle. Image

Options

G1 Physics · Accepted Answer

Step 1: Over a complete thermodynamic cycle, the system returns to its initial state; therefore ΔU_cycle = 0. Step 2: First law over a cycle gives Q_net = W_net. Step 3: Net work by the gas is the enclosed area on a P–V graph. For clockwise traversal the work is positive. Step 4: W_net = (P_high − P_low)(V_right − V_left) = (300 − 100)(5 − 2). Step 5: W_net = 200 × 3 = 600 J. Final answer: Net heat added over the cycle = +600 J (Option C). 'Total heat supplied' is interpreted as algebraic net h…

One mole of an ideal monatomic gas undergoes the clockwise rectangular cyclic process a → b → c → d → a on a P–V diagram: P_high = 300 Pa, P_low = 100 Pa, V_left = 2 m³, V_right = 5 m³. Find the NET heat supplied over one cycle. Image