JEE Mains 2025 8 April Evening Shift (Shift 2) physics questions with solutions

Showing 1–10 of 25 questions

• MCQeasyElectrostaticsconductor and its properties

  Two isolated conducting spheres of radii R and 3R initially have the same surface charge density σ. They are brought into contact and then separated. If the final surface charge densities on the smaller and larger spheres are σ₁ and σ₂ respectively, the ratio σ₁/σ₂ is:

  Options

  • Option A

    1/9

  • Option B

    9

  • Option C

    1/3

  • Option D

    3

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• IntegermediumRotational Motiontorque and rotational equilibrium

  A thin solid disc of mass 1 kg rotates about a diameter at 1800 rpm. A constant external torque 25π N·m acts for 40 s, increasing its speed to 2100 rpm. Find the diameter of the disc in metres.

  Your answer

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• MCQmediumUnit dimension and errorError and its addition ,subtraction,multipication and division

  A quantity is given by Q = X⁻² · Y³⁄² · Z⁻²⁄⁵. The fractional errors in X, Y and Z are 0.1, 0.2 and 0.5 respectively. The maximum fractional error in Q is:

  Options

  • Option A

    0.1

  • Option B

    0.8

  • Option C

    0.7

  • Option D

    0.6

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• MCQmediumWave Motionreflaction ,refraction of string wave and superposition of wave

  Two waves are y₁ = 4 sin(kx-ωt) and y₂ = 2 sin(kx-ωt + 2π/3). The amplitude and phase of the resultant wave, relative to y₁, are:

  Options

  • Option A

    6, 2π/3

  • Option B

    6, π/3

  • Option C

    √3, π/6

  • Option D

    2√3, π/6

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• MCQeasyThermodyanmicsheat and principle of calorimeter

  Water falls from a height of 200 m into a pool. Assuming no heat is lost, find the rise in temperature of the water. Take g = 10 m s⁻² and specific heat of water s = 4200 J kg⁻¹ K⁻¹.

  Options

  • Option A

    0.23 K

  • Option B

    0.36 K

  • Option C

    0.14 K

  • Option D

    0.48 K

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• MCQmediumWave Opticsyoung's dubble slit experiments

  In Young's double-slit experiment, white light is used. One slit is covered with a red filter and the other with a green filter. What is observed?

  Options

  • Option A

    Separate red and green interference patterns are formed

  • Option B

    No stable interference fringes are formed

  • Option C

    Alternate red and green interference fringes are formed

  • Option D

    Each fringe has a green centre and red outer edges

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• MCQeasyNewtons law of motion and Frictionnewton second law and problem based on it

  A 2 kg body initially has velocity v = (3, 4, 0) m/s. It enters a region with a constant force of 6 N along +z and remains there for 5/3 s. Its velocity on leaving the region is:

  Options

  • Option A

    (4, 3, 5) m/s

  • Option B

    (3, 4, 5) m/s

  • Option C

    (3, 4, -5) m/s

  • Option D

    (3, 4, √5) m/s

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• MCQeasyElectrostaticspotential energy and electric potential

  Assertion (A): Work done in moving a test charge between two points inside a uniformly charged spherical shell is zero, irrespective of the path. Reason (R): Electrostatic potential everywhere inside a uniformly charged spherical shell is constant and equal to its surface potential. Choose the correct answer.

  Options

  • Option A

    A is true but R is false

  • Option B

    Both A and R are true and R is the correct explanation of A

  • Option C

    A is false but R is true

  • Option D

    Both A and R are true but R is NOT the correct explanation of A

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• MCQeasyThermodyanmicsthermodynmic process and work done

  A monoatomic ideal gas with γ = 5/3 is stored in a thermally insulated container and is suddenly compressed to 1/8 of its initial volume. The ratio Pf/Pi is:

  Options

  • Option A

    16

  • Option B

    40

  • Option C

    32

  • Option D

    28

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• MCQmediumMagnetic effect of currentbiot savart law and magnetic field due to straight conductor ,arc and ring

  A current I enters a square loop ABCD of side a at A and leaves at C. Resistance of path ABC is r, while resistance of path ADC is 2r. The magnitude of the magnetic field at the centre of the square is:

  

  Options

  • Option A

    3πμ₀I/(√2a)

  • Option B

    μ₀I/(2πa)

  • Option C

    √2μ₀I/(3πa)

  • Option D

    2μ₀I/(3πa)

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