Paper 2 physics questions with solutions

Showing 1–10 of 16 questions

• NumericdifficultCurrent electricityElectrical Instruments: Galvanometer, Ammeter, Voltmeter & Potentiometer

  As shown in the figure, the resistance of a galvanometer G can be found by the half-deflection method. Here the resistance R₂ is adjusted such that when the key K is closed the deflection in the galvanometer becomes half of the value as compared to when K is open. Half-deflection is obtained at R₂ = 4 Ω and thus the galvanometer resistance is found to be 6 Ω. In this half-deflection condition the current (in mA) through the resistor R₁ is:

  

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• ParagraphdifficultCapacitorCapacitors with Dielectrics

  A container of height 2 m, length 2 m and breadth 1 m is made of insulating vertical walls and two large area horizontal metal plates M₁ and M₂ which extend far beyond the vertical walls in all directions. The container is partitioned into two equal chambers with a thin insulating vertical wall. The partition wall contains a small hole of cross-sectional area √10 cm² near its bottom edge. Initially the hole is closed and the left chamber of the container is completely filled with a liquid of dielectric constant ε(r) = 15 and the right chamber is empty, ε(r) = 1. At time t = 0, the hole is opened and the liquid flows from the left chamber to the right chamber. In both the chambers, the space above the liquid has ε(r) = 1 and is maintained at atmospheric pressure. The schematic of the container at a time t > 0 is shown in the figure. [Given: acceleration due to gravity is 10 m s⁻².]

  

  Sub-question 1

  The height (in m) of the liquid in left chamber at t = 500 s is:

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  Sub-question 2

  The difference in the capacitance (in F) between the metal plates at t = 0 and that at t = 500 s is (8 - n)ε₀, where ε₀ is the permittivity of free space. The value of n is:

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• NumericdifficultUnits, Dimensions, Measurements and ErrorsSystems of Units and Unit Conversion

  In a new system of units, the units of mass, length, time and current are 5 kg, 5 m, 5 s and 5 A, respectively. If μ₀ and ε₀ are the permeability and permittivity of free space, respectively, then in this new system of units, the magnitude of one SI unit of √(μ₀/ε₀), is:

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• NumericmediumUnits, Dimensions, Measurements and ErrorsVernier Calipers and Screw Gauge: Measurement and Errors

  Two thin wires, Wire-1 of diameter 0.650 mm and Wire-2 of unknown diameter d are given. To obtain the value of d, the diameters of the two wires are measured with a screw gauge. The screw gauge has a pitch of 0.5 mm and there are 100 divisions on the circular scale (CS). The smallest division on the linear scale (LS) is 0.5 mm. The table shows the readings of LS and CS for the measurements. The value of d (in μm) is:

  

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• MCQdifficultSimple Harmonic MotionTime Period of Linear Simple Harmonic Motion

  A particle of mass m, and angular momentum ℓ is moving in a circular orbit of radius r₀ under the influence of an attractive force F(r) directed radially inward with magnitude k/r². Keeping its angular momentum unchanged, the particle is displaced radially by a small distance δr ≪ r₀, due to which its radial distance varies periodically. The corresponding time period is:

  Options

  • Option A

    2πℓ³/(mk²)

  • Option B

    2π√(m/k)

  • Option C

    2πℓ³/(3mk²)

  • Option D

    2πℓ³/(5mk²)

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• NumericmediumWave OpticsPolarisation of Light

  As shown in the figure, a ray AB of unpolarized light enters from water of refractive index n(w) = 4/3 into a medium of refractive index n(p) = 4/√3 after passing through a glass plate of refractive index n(g) = 1.5 and a layer of water. At a particular incident angle i the reflected ray CD is polarized in the direction as shown in the figure. The value of i (in degrees) is:

  

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• Multi-correctdifficultGeometrical opticsPrisms & Thin Prisms

  Consider two isosceles prisms 1 and 2 with prism angles A₁ and A₂ and refractive indices n₁ and n₂, respectively, as shown in the figure. The faces a₁b₁ and a₂b₂ are parallel to each other and perpendicular to the mirror M. If a ray of light is incident on the face a₁c₁ and emerges from the face a₂c₂, then the correct statement(s) is/are:

  

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  • Option A

    If both the prisms are at minimum deviation condition, then n₂/n₁ = sin(A₁/2)/sin(A₂/2).

  • Option B

    If prism 2 is at minimum deviation condition, then sin i₁ = n₂ sin(A₂/2) is always true.

  • Option C

    If both prisms 1 and 2 are thin and are at minimum deviation condition with angles of deviation δ(min,1) and δ(min,2), respectively, then θ = δ(min,1)/[2(n₁-1)] + δ(min,2)/[2(n₂-1)].

  • Option D

    If prism 1 is at minimum deviation condition, then sin i₂ = n₁ sin(A₁/2) is always true.

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• Multi-correctmediumElectrostaticElectric Potential & Potential Energy

  Two charges Q₁ = q and Q₂ = mq are placed at the points P₁(a,b) and P₂(ma,mb), respectively, in the XY plane, where a,b ≠ 0 and m ≠ 0,1. If V₁ is the potential at a point in the XY plane due to charge Q₁ and V₂ is the potential at that point due to charge Q₂. Correct statement(s) for the points at which |V₁| = |V₂| is/are:

  Select all that apply

  • Option A

    For m = -1, locus of these points is ax + by = 0.

  • Option B

    For m = 2, the locus of these points is a circle of radius (2/3)√(a²+b²) centered at ((2/3)a,(2/3)b).

  • Option C

    For m = -2, the locus of these points is a circle of radius 2√(a²+b²) centered at (2a,2b).

  • Option D

    For m = -3, locus of these points is 3bx + 3ay = 0.

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• NumericdifficultWave OpticsDiffraction of Light

  In a single slit diffraction experiment, a slit of width (0.016 ± 0.002) mm is used to measure the wavelength of a monochromatic light source. In the diffraction pattern, the angular distance between the central maximum and first minimum is measured to be (2° ± 40′). The value of the fractional error in the measurement of wavelength is: [Given: sin(2°) = 0.035]

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• MCQmediumGeometrical opticsPrisms & Thin Prisms

  A beam of polychromatic light passes through a thin prism of prism angle 6°. The refractive index of the material of the prism varies with wavelength λ as n(λ) = αλ + β/λ², where α = 3 μm⁻¹ and β = 0.096 μm². If λ(min) is the wavelength at which the angle of minimum deviation D(min) is smallest, then the correct value of D(min) at λ(min) is:

  Options

  • Option A

    6.4°

  • Option B

    4.8°

  • Option C

    3.2°

  • Option D

    2.4°

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