Free physics question bank

centripital force and centrifugal force questions with solutions

Practice Circular Motion for JEE Main, JEE Advanced, NEET, and Classes 11–12. Attempt each question, then open it for the full solution.

Showing 1–10 of 28 questions

  • NumericeasyCircular Motion

    A conical pendulum has a bob of mass 2 kg and its string makes 60° with the vertical. Take g=10 m/s². If the string tension is N newton, find N.

    JEE MainsNEETJEE Advanced

    Open question & full solution →
  • NumericmediumCircular Motion

    A particle of mass 2 kg moves on a smooth horizontal table in a circle of radius 0.5 m with angular speed 4 rad/s. It is attached to a string passing through a smooth hole at the centre of the table, and the other end supports a hanging mass M which remains stationary. Take g=10 m/s². If 10M=N, find N.

    JEE MainsNEETJEE Advanced

    Open question & full solution →
  • NumericmediumCircular Motion

    Two equal masses of 1 kg each are connected by a spring of force constant 10 N/m and natural length 1 m. They rotate about their common centre of mass with angular speed 2 rad/s. If the spring extension is x and 100x=N, find N.

    JEE MainsNEETJEE Advanced

    Open question & full solution →
  • A/RmediumCircular Motion

    Evaluate the following statements.

    Assertion

    Assertion (A): In a frame rotating with the radial groove, the outward radial acceleration of the bead can be described using centrifugal force.

    Reason

    Reason (R): In that rotating frame, the centrifugal pseudo force mω²r acts radially outward and gives the radial equation m(d²r/dt²)=mω²r.

    Options

    JEE MainsNEETJEE Advanced

    Open question & full solution →
  • NumericeasyCircular Motion

    A conical pendulum has string length 1.25 m and cosθ=0.8. Take g=π² m/s². If the square of its time period is N s², find N.

    JEE MainsNEETJEE Advanced

    Open question & full solution →
  • NumericeasyCircular Motion

    A bead is in a smooth radial groove of a disc rotating with constant angular speed 3 rad/s. At an instant its distance from the centre is 2 m. If its radial acceleration d²r/dt²=N m/s², find N.

    JEE MainsNEETJEE Advanced

    Open question & full solution →
  • MCQmediumCircular Motion

    A bead is initially at distance r₀ from the centre of a smooth radial groove on a disc rotating with constant angular speed ω. Its initial radial speed is zero. Its radial position after time t is:

    Options

    JEE MainsNEETJEE Advanced

    Open question & full solution →
  • MCQmediumCircular Motion

    A small bead can slide without friction in a radial groove of a horizontal disc rotating with constant angular speed ω. If r is the bead's distance from the centre, its radial equation of motion in an inertial frame is:

    Options

    JEE MainsNEETJEE Advanced

    Open question & full solution →
  • NumericmediumCircular Motion

    A conical pendulum has string length 5 m and its bob moves in a horizontal circle of radius 3 m. Take g=10 m/s². If ω²=N/2, find N.

    JEE MainsNEETJEE Advanced

    Open question & full solution →
  • MCQmediumCircular Motion

    A car is moving with a constant speed of 20 m/s in a circular horizontal track of radius 40 m. A bob is suspended from the roof of the car by a massless string. The angle made by the string with the vertical will be: (Take g = 10 m/s²)

    Options

    JEE Mains25 January 2023Morning Shift

    Open question & full solution →