A particle of mass 2 kg moves on a smooth horizontal table in a circle of radius 0.5 m with angular speed 4 rad/s. It is attached to a string passing through a smooth hole at the centre of the table, and the other end supports a hanging mass M which remains stationary. Take g=10 m/s². If 10M=N, find N.
Physics · Circular Motion · centripital force and centrifugal force
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Question

A particle of mass 2 kg moves on a smooth horizontal table in a circle of radius 0.5 m with angular speed 4 rad/s. It is attached to a string passing through a smooth hole at the centre of the table, and the other end supports a hanging mass M which remains stationary. Take g=10 m/s². If 10M=N, find N.

Physics · Circular Motion · centripital force and centrifugal force

G1 Physics · Accepted Answer

For the particle on the table, the string tension provides the centripetal force: T = mω²r = 2×4²×0.5 = 2×16×0.5 = 16 N. The hanging mass is stationary, so its forces balance: Mg=T. With g=10 m/s², 10M=16. Therefore N=16.